C语言中怎么用easyx实现消砖块游戏
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一、最终效果展示
效果图如下:
二、绘制静态的挡板
代码如下:
#include<conio.h>#include<graphics.h>#define High 480 //游戏画面尺寸#define Width 640//全局变量int ball_x,ball_y;//小球的坐标int ball_vx,ball_vy;//小球的速度int radius;//小球的半径int bar_x,bar_y;//挡板的中心坐标int bar_high,bar_width;//挡板的高度和宽度int bar_left,bar_right,bar_top,bar_bottom;//挡板的左右上下位置坐标void startup()//数据的初始化{ ball_x=Width/2; ball_y=High/2; ball_vx=1; ball_vy=1; radius=20; bar_high=High/20; bar_width=Width/5; bar_x=Width/2; bar_y=High-bar_high/2; bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; initgraph(Width,High); BeginBatchDraw();}void clean()//显示画面{ setcolor(BLACK);//绘制黑线,黑色填充的圆 setfillcolor(BLACK); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黑色,黑色填充的挡板}void show()//显示画面{ setcolor(YELLOW);//绘制黄线,绿色填充的圆 setfillcolor(GREEN); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黄色,绿色填充的挡板 FlushBatchDraw(); Sleep(3);}void updateWithoutInput()//与用户输入无关的更新{ ball_x=ball_x+ball_vx; ball_y=ball_y,ball_vy;//更新小球的坐标 if( (ball_x<=radius)||(ball_x>=Width-radius)) ball_vx=-ball_vx; if( (ball_y<=radius)||(ball_y>=High-radius)) ball_vy=-ball_vy;}void updateWithInput()//与用户输入有关的更新{}void gameover(){ EndBatchDraw(); closegraph();}int main(){ startup();//数据的初始化 while(1) { clean();//把之前绘制的内容清除 updateWithoutInput();//与用户输入无关的更新 updateWithInput();//与用户输入有关的更新 show();//显示新画面 }}
效果图如下:
三、控制挡板
代码如下:
#include<conio.h>#include<graphics.h>#define High 480 //游戏画面尺寸#define Width 640//全局变量int ball_x,ball_y;//小球的坐标int ball_vx,ball_vy;//小球的速度int radius;//小球的半径int bar_x,bar_y;//挡板的中心坐标int bar_high,bar_width;//挡板的高度和宽度int bar_left,bar_right,bar_top,bar_bottom;//挡板的左右上下位置坐标void startup()//数据的初始化{ ball_x=Width/2; ball_y=High/2; ball_vx=1; ball_vy=1; radius=20; bar_high=High/20; bar_width=Width/5; bar_x=Width/2; bar_y=High-bar_high/2; bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; initgraph(Width,High); BeginBatchDraw();}void clean()//显示画面{ setcolor(BLACK);//绘制黑线,黑色填充的圆 setfillcolor(BLACK); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黑色,黑色填充的挡板}void show()//显示画面{ setcolor(YELLOW);//绘制黄线,绿色填充的圆 setfillcolor(GREEN); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黄色,绿色填充的挡板 FlushBatchDraw(); Sleep(3);}void updateWithoutInput()//与用户输入无关的更新{ //挡板和小球碰撞,小球反弹 if(((ball_y+radius>=bar_top)&&(ball_y+radius<bar_bottom-bar_high/3)) ||((ball_y-radius<=bar_bottom)&&(ball_y-radius>bar_top-bar_high/3))) if((ball_x>=bar_left)&&(ball_x<=bar_right)) ball_vy=-ball_vy; ball_x=ball_x+ball_vx; ball_y=ball_y,ball_vy;//更新小球的坐标 if( (ball_x<=radius)||(ball_x>=Width-radius)) ball_vx=-ball_vx; if( (ball_y<=radius)||(ball_y>=High-radius)) ball_vy=-ball_vy;}void updateWithInput()//与用户输入有关的更新{ char input; if(kbhit()) { input=getch(); if(input=='a'&&bar_left>0) { bar_x=bar_x-15;//位置左移 bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; } if(input=='d'&&bar_right<Width) { bar_x=bar_x+15;//位置左移 bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; } if(input=='w'&&bar_top>0) { bar_y=bar_y-15;//位置左移 bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; } if(input=='s'&&bar_bottom<High) { bar_y=bar_y+15;//位置右移 bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; } }}void gameover(){ EndBatchDraw(); closegraph();}int main(){ startup();//数据的初始化 while(1) { clean();//把之前绘制的内容清除 updateWithoutInput();//与用户输入无关的更新 updateWithInput();//与用户输入有关的更新 show();//显示新画面 }}
效果图如下:
四、消砖块
代码如下:
#include<conio.h>#include<graphics.h>#define High 480 //游戏画面尺寸#define Width 640#define Brick_num 10//全局变量int ball_x,ball_y;//小球的坐标int ball_vx,ball_vy;//小球的速度int radius;//小球的半径int bar_x,bar_y;//挡板的中心坐标int bar_high,bar_width;//挡板的高度和宽度int bar_left,bar_right,bar_top,bar_bottom;//挡板的左右上下位置坐标int isBrickExisted[Brick_num];//每个砖块是否存在,1为存在,0为没有了int brick_high,brick_width;//每个砖块的高度和宽度void startup()//数据的初始化{ ball_x=Width/2; ball_y=High/2; ball_vx=1; ball_vy=1; radius=20; bar_high=High/20; bar_width=Width/5; bar_x=Width/2; bar_y=High-bar_high/2; bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; brick_width=Width/Brick_num; brick_high=High/Brick_num; int i; for(i=0;i<Brick_num;i++) isBrickExisted[i]=1; initgraph(Width,High); BeginBatchDraw();}void clean()//显示画面{ setcolor(BLACK);//绘制黑线,黑色填充的圆 setfillcolor(BLACK); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黑色,黑色填充的挡板 int i,brick_left,brick_right,brick_top,brick_bottom; for(i=0;i<Brick_num;i++) { brick_left=i*brick_width; brick_right=brick_left+brick_width; brick_top=0; brick_bottom=brick_high; if(!isBrickExisted[i])//砖块没有了,绘制黑色 fillrectangle(brick_left,brick_top,brick_right,brick_bottom); }}void show()//显示画面{ setcolor(YELLOW);//绘制黄线,绿色填充的圆 setfillcolor(GREEN); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黄色,绿色填充的挡板 int i,brick_left,brick_right,brick_top,brick_bottom; for(i=0;i<Brick_num;i++) { brick_left=i*brick_width; brick_right=brick_left+brick_width; brick_top=0; brick_bottom=brick_high; if(isBrickExisted[i])//砖块存在,绘制砖块 { setcolor(WHITE); setfillcolor(RED); fillrectangle(brick_left,brick_top,brick_right,brick_bottom);//绘制砖块 } } FlushBatchDraw(); Sleep(3);}void updateWithoutInput()//与用户输入无关的更新{ //挡板和小球碰撞,小球反弹 if(((ball_y+radius>=bar_top)&&(ball_y+radius<bar_bottom-bar_high/3)) ||((ball_y-radius<=bar_bottom)&&(ball_y-radius>bar_top-bar_high/3))) if((ball_x>=bar_left)&&(ball_x<=bar_right)) ball_vy=-ball_vy; ball_x=ball_x+ball_vx; ball_y=ball_y+ball_vy;//更新小球的坐标 //小球和边界碰撞 if( (ball_x<=radius)||(ball_x>=Width-radius)) ball_vx=-ball_vx; if( (ball_y<=radius)||(ball_y>=High-radius)) ball_vy=-ball_vy; //判断小球是否和某个砖块碰撞 int i,brick_left,brick_right,brick_top,brick_bottom; for(i=0;i<Brick_num;i++) { if(isBrickExisted[i])//砖块存在才判断 { brick_left=i*brick_width; brick_right=brick_left+brick_width; brick_bottom=brick_high; if((ball_y==brick_bottom+radius)&&(ball_x>=brick_left)&&(ball_x<= brick_right)) { isBrickExisted[i]=0; ball_vy=-ball_vy; } } }}void updateWithInput()//与用户输入有关的更新{ char input; if(kbhit()) { input=getch(); if(input=='a'&&bar_left>0) { bar_x=bar_x-15;//位置左移 bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; } if(input=='d'&&bar_right<Width) { bar_x=bar_x+15;//位置左移 bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; } }}void gameover(){ EndBatchDraw(); closegraph();}int main(){ startup();//数据的初始化 while(1) { clean();//把之前绘制的内容清除 updateWithoutInput();//与用户输入无关的更新 updateWithInput();//与用户输入有关的更新 show();//显示新画面 }}
效果图如下:
五、鼠标交互
先看一个关于鼠标交互的实例
#include<graphics.h>#include<conio.h>int main(void){ initgraph(640,480);//初始化图形窗口 MOUSEMSG m;//定义鼠标消息 while(1) { m=GetMouseMsg();//获取一条鼠标消息 if(m.uMsg==WM_MOUSEMOVE) { putpixel(m.x,m.y,WHITE);//鼠标移动的时候画小白点 } else if(m.uMsg==WM_LBUTTONDOWN) { rectangle(m.x-5,m.y-5,m.x+5,m.y+5); //鼠标左键按下时在鼠标位置画一个方块 } else if(m.uMsg==WM_RBUTTONUP) { circle(m.x,m.y,10); //鼠标右键按下时在鼠标位置画一个圆 } } return 0;}
用鼠标控制挡板移动,按鼠标左键初始化小球位置
代码如下:
#include<conio.h>#include<graphics.h>#define High 480 //游戏画面尺寸#define Width 640#define Brick_num 10//全局变量int ball_x,ball_y;//小球的坐标int ball_vx,ball_vy;//小球的速度int radius;//小球的半径int bar_x,bar_y;//挡板的中心坐标int bar_high,bar_width;//挡板的高度和宽度int bar_left,bar_right,bar_top,bar_bottom;//挡板的左右上下位置坐标int isBrickExisted[Brick_num];//每个砖块是否存在,1为存在,0为没有了int brick_high,brick_width;//每个砖块的高度和宽度void startup()//数据的初始化{ ball_x=Width/2; ball_y=High/2; ball_vx=1; ball_vy=1; radius=20; bar_high=High/20; bar_width=Width/5; bar_x=Width/2; bar_y=High-bar_high/2; bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; brick_width=Width/Brick_num; brick_high=High/Brick_num; int i; for(i=0;i<Brick_num;i++) isBrickExisted[i]=1; initgraph(Width,High); BeginBatchDraw();}void clean()//显示画面{ setcolor(BLACK);//绘制黑线,黑色填充的圆 setfillcolor(BLACK); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黑色,黑色填充的挡板 int i,brick_left,brick_right,brick_top,brick_bottom; for(i=0;i<Brick_num;i++) { brick_left=i*brick_width; brick_right=brick_left+brick_width; brick_top=0; brick_bottom=brick_high; if(!isBrickExisted[i])//砖块没有了,绘制黑色 fillrectangle(brick_left,brick_top,brick_right,brick_bottom); }}void show()//显示画面{ setcolor(YELLOW);//绘制黄线,绿色填充的圆 setfillcolor(GREEN); fillcircle(ball_x,ball_y,radius); bar(bar_left,bar_top,bar_right,bar_bottom);//绘制黄色,绿色填充的挡板 int i,brick_left,brick_right,brick_top,brick_bottom; for(i=0;i<Brick_num;i++) { brick_left=i*brick_width; brick_right=brick_left+brick_width; brick_top=0; brick_bottom=brick_high; if(isBrickExisted[i])//砖块存在,绘制砖块 { setcolor(WHITE); setfillcolor(RED); fillrectangle(brick_left,brick_top,brick_right,brick_bottom);//绘制砖块 } } FlushBatchDraw(); Sleep(3);}void updateWithoutInput()//与用户输入无关的更新{ //挡板和小球碰撞,小球反弹 if(((ball_y+radius>=bar_top)&&(ball_y+radius<bar_bottom-bar_high/3)) ||((ball_y-radius<=bar_bottom)&&(ball_y-radius>bar_top-bar_high/3))) if((ball_x>=bar_left)&&(ball_x<=bar_right)) ball_vy=-ball_vy; ball_x=ball_x+ball_vx; ball_y=ball_y+ball_vy;//更新小球的坐标 //小球和边界碰撞 if( (ball_x<=radius)||(ball_x>=Width-radius)) ball_vx=-ball_vx; if( (ball_y<=radius)||(ball_y>=High-radius)) ball_vy=-ball_vy; //判断小球是否和某个砖块碰撞 int i,brick_left,brick_right,brick_top,brick_bottom; for(i=0;i<Brick_num;i++) { if(isBrickExisted[i])//砖块存在才判断 { brick_left=i*brick_width; brick_right=brick_left+brick_width; brick_bottom=brick_high; if((ball_y==brick_bottom+radius)&&(ball_x>=brick_left)&&(ball_x<= brick_right)) { isBrickExisted[i]=0; ball_vy=-ball_vy; } } }}void updateWithInput()//与用户输入有关的更新{ MOUSEMSG m;//定义鼠标信息 if(MouseHit())//这个函数用于检测当前是否有鼠标消息 { m=GetMouseMsg();//获取一条鼠标消息 if(m.uMsg==WM_MOUSEMOVE) { //挡板的位置等于鼠标所在的位置 bar_x=m.x; bar_y=m.y; bar_left=bar_x-bar_width/2; bar_right=bar_x+bar_width/2; bar_top=bar_y-bar_high/2; bar_bottom=bar_y+bar_high/2; } else if(m.uMsg==WM_LBUTTONDOWN) { ball_x=bar_x;//初始化小球的位置为挡板上面中心 ball_y=bar_top-radius-3; } }}void gameover(){ EndBatchDraw(); closegraph();}int main(){ startup();//数据的初始化 while(1) { clean();//把之前绘制的内容清除 updateWithoutInput();//与用户输入无关的更新 updateWithInput();//与用户输入有关的更新 show();//显示新画面 }}
效果图如下:
感谢各位的阅读,以上就是“C语言中怎么用easyx实现消砖块游戏”的内容了,经过本文的学习后,相信大家对C语言中怎么用easyx实现消砖块游戏这一问题有了更深刻的体会,具体使用情况还需要大家实践验证。这里是编程网,小编将为大家推送更多相关知识点的文章,欢迎关注!
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