ORA-14522: Partition-level default tablespace string block size [string] for string string does not

文档解释

ORA-14522: Partition-level default tablespace string block size [string] for string string does not match existing string block size [string]

Cause: A DDL statement was issued that would require creation of a new subpartition in one of the partition-level default tablespaces of an existing composite partitioned object. However, the partition-level default tablespace block size does not match the block size of the partitioned object.

Action: Either (1) Modify the partition-level default tablespace of the appropriate partition of the partitioned object to a tablespace of the same block size as the object and then retry the DDL command, OR (2) Ensure that tablespaces of the correct block size are specified for all new subpartitions being created.

这是一个Oracle数据库错误，它表明在给定表中，分区的默认表空间字符串块大小不匹配现有的字符串块大小。

官方解释

ORA-14522 表示在给定表中，分区级别的默认表空间字符串大小（诸如8K）与现有分区的块（诸如4K）字符串块大小不匹配。

常见案例

ORA-14522 错误通常发生在尝试向现有分区的表中添加新的分区时，这时会存在表空间字符串块大小不匹配的情况。

正常处理方法及步骤

要解决 ORA-14522 错误，首先要确定分区中表空间字符串块大小是否正确。如果不正确，可以运行ALTER TABLE命令并指定正确的块大小。另外，您还可以使用 ALTER TABLESPACE 命令来更改表空间的存储块大小，但某些情况下，您可能需要重新划分重新生成表空间。