Android 实现双击退出的功能

实现android双击后退键退出当前APP功能

实现该功能基本思路是，

1， 监听后退键 ， 比较两次后退间隔 ， 低于两秒则出发退出

2， 退出当前APP

我选择在基类中BaseActivity 中设置监听，代码如下：

 public void onBackPressed() {
    //Preferences 中获取是否双击退出
    boolean isDoubleClick = true;
    //BaseApplication.get("ifDoubleClickedBack", true);
    if (isDoubleClick) {
      long curTime = SystemClock.uptimeMillis();
      if ((curTime - mBackPressedTime) < (2 * 1000)) {
        finish();
        //activity栈管理
        AppManager.getAppManager().AppExit();
      } else {
        mBackPressedTime = curTime;
        Toast.makeText(this, "再次点击退出", Toast.LENGTH_SHORT).show();
      }
    } else {
      finish();
    }
  }

在退出当前APP中，参考开源中国，封装了activity栈

实例代码：

public class AppManager {
  private static Stack<Activity> activityStack;
  private static AppManager instance;
  private AppManager() {
  }
  
  public static AppManager getAppManager() {
    if (instance == null) {
      instance = new AppManager();
    }
    if (activityStack == null) {
      activityStack = new Stack<Activity>();
    }
    return instance;
  }
  
  public static Activity getActivity(Class<?> cls) {
    if (activityStack != null)
      for (Activity activity : activityStack) {
        if (activity.getClass().equals(cls)) {
          return activity;
        }
      }
    return null;
  }
  
  public void addActivity(Activity activity) {
    activityStack.add(activity);
  }
  
  public Activity currentActivity() {
    Activity activity = activityStack.lastElement();
    return activity;
  }
  
  public void finishActivity() {
    Activity activity = activityStack.lastElement();
    finishActivity(activity);
  }
  
  public void finishActivity(Activity activity) {
    if (activity != null && activityStack.contains(activity)) {
      activityStack.remove(activity);
      activity.finish();
    }
  }
  
  public void removeActivity(Activity activity) {
    if (activity != null && activityStack.contains(activity)) {
      activityStack.remove(activity);
    }
  }
  
  public void finishActivity(Class<?> cls) {
    for (Activity activity : activityStack) {
      if (activity.getClass().equals(cls)) {
        finishActivity(activity);
        break;
      }
    }
  }
  
  public void finishAllActivity() {
    for (int i = 0, size = activityStack.size(); i < size; i++) {
      if (null != activityStack.get(i)) {
        finishActivity(activityStack.get(i));
      }
    }
    activityStack.clear();
  }
  
  public void AppExit() {
    try {
      finishAllActivity();
      // System.exit(0);
    } catch (Exception e) {
    }
  }
}

思路就是在每次activity 压入activity栈中管理

在退出时遍历栈，挨个finish

希望本文所述对大家的Android程序设计有所帮助。

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