Java并发之嵌套管程锁死详解

Thread 1 synchronizes on AThread 1 synchronizes on B (while synchronized on A)Thread 1 decides to wait for a signal from another thread before continuingThread 1 calls B.wait() thereby releasing the lock on B, but not A.Thread 2 needs to lock both A and B (in that sequence)    to send Thread 1 the signal.Thread 2 cannot lock A, since Thread 1 still holds the lock on A.Thread 2 remain blocked indefinately waiting for Thread1    to release the lock on AThread 1 remain blocked indefinately waiting for the signal from    Thread 2, thereby    never releasing the lock on A, that must be released to make    it possible for Thread 2 to send the signal to Thread 1, etc.