Java8中Stream流求最大值最小值
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文章目录
java中各种类型用Stream流求最大值最小值
一、BigDecimal 求最大值和最小值
1. stream().reduce()实现
List<BigDecimal> list = new ArrayList<>(Arrays.asList(new BigDecimal("1"), new BigDecimal("2"))); BigDecimal max = list.stream().reduce(list.get(0), BigDecimal::max); BigDecimal min = list.stream().reduce(list.get(0), BigDecimal::min);2. stream().max()或stream().min()实现
List<BigDecimal> list = new ArrayList<>(Arrays.asList(new BigDecimal("1"), new BigDecimal("2"))); BigDecimal max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); BigDecimal min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);二、Integer 求最大值和最小值
1. stream().reduce()实现
List<Integer> list = new ArrayList<>(Arrays.asList(1, 2)); Integer max = list.stream().reduce(list.get(0), Integer::max); Integer min = list.stream().reduce(list.get(0), Integer::min);2. Collectors.summarizingInt()实现
List<Integer> list = new ArrayList<>(Arrays.asList(1, 2)); IntSummaryStatistics intSummaryStatistics = list.stream().collect(Collectors.summarizingInt(x -> x)); Integer max = intSummaryStatistics.getMax(); Integer min = intSummaryStatistics.getMin();3. stream().max()或stream().min()实现
List<Integer> list = new ArrayList<>(Arrays.asList(1, 2)); Integer max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); Integer min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);三、Long 求最大值和最小值
1. stream().reduce()实现
List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L)); Long max = list.stream().reduce(list.get(0), Long::max); Long min = list.stream().reduce(list.get(0), Long::min);2. Collectors.summarizingLong()实现
List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L)); LongSummaryStatistics summaryStatistics = list.stream().collect(Collectors.summarizingLong(x -> x)); Long max = summaryStatistics.getMax(); Long min = summaryStatistics.getMin();3. stream().max()或stream().min()实现
List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L)); Long max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); Long min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);四、Double 求最大值和最小值
1. stream().reduce()实现
List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d)); Double max = list.stream().reduce(list.get(0), Double::max); Double min = list.stream().reduce(list.get(0), Double::min);2. Collectors.summarizingLong()实现
List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d)); DoubleSummaryStatistics summaryStatistics = list.stream().collect(Collectors.summarizingDouble(x -> x)); Double max = summaryStatistics.getMax(); Double min = summaryStatistics.getMin();3. stream().max()或stream().min()实现
List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d)); Double max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); Double min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);来源地址：https://blog.csdn.net/qq_43842093/article/details/129103037
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