Shell脚本监控网站页面正常打开情况
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现在单位为了省钱,我用了shell脚本,简单的写了一个监控。通过curl一个固定页面的200状态码,如果是200,就说网站是正常的,如果不是200就自动重启网站,然后发邮件到QQ邮箱。自己在上QQ的同时,通过微信也可以收到报警,不但可以收到报警,还可以解决问题。基本上也可以解决web的故障。
#! /bin/bash
source /etc/profile
A="web is Good !"
ip=`ifconfig eth0 | grep "inet addr" | awk -F "[: ]+" '{print $4}'`
tt1=`curl -I -s http://xx.8x.18x.xx:1657/product/pro_detail_-rg000785.shtml | head -1 | cut -d " " -f2`
Process=`ps -ef | grep java | egrep "tomcat1" | awk -F " " '{print $2}'`
if [ $tt1 = "200" ]
then
echo "$A" >>/home/taoyake/scripts/website-error.`date +%F`.log
else
/opt/tomcat1/bin/shutdown.sh
cd /opt/tomcat1/work/Catalina/
rm -rf localhost
kill -9 $Process
/opt/tomcat1/bin/startup.sh
echo "1657 is reload." >>/home/taoyake/scripts/website-error.`date +%F`.log
echo "1657 is reload." | mail -s "website-1657" "505065674@qq.com"
fi
more /home/taoyake/scripts/reload_website-1658.sh
#! /bin/bash
source /etc/profile
B="1658 is Good !"
ip=`ifconfig eth0 | grep "inet addr" | awk -F "[: ]+" '{print $4}'`
tt1=`curl -I -s http://xx.xx.183.xx:1658/product/pro_detail_-rg000785.shtml | head -1 | cut -d " " -f2`
Process=`ps -ef | grep java | egrep "tomcat2" | awk -F " " '{print $2}'`
if [ $tt1 = "200" ]
then
echo "$B" >>/home/taoyake/scripts/website-1658-access.`date +%F`.log
else
/opt/tomcat2/bin/shutdown.sh
cd /opt/tomcat2/work/Catalina/
rm -rf localhost
kill -9 $Process
/opt/tomcat2/bin/startup.sh
echo "1658 is reload." >>/home/taoyake/scripts/website-1658-error.`date +%F`.log
echo "1658 is reload." | mail -s "website-1658" "505065674@qq.com"
fi
[root@web ~]# crontab -l
*/10 * * * * /usr/sbin/ntpdate time.windows.com >/dev/null 2>&1
*/5 * * * * /bin/sh /home/taoyake/scripts/reload_website.sh >/dev/null 2>&1
*/5 * * * * /bin/sh /home/taoyake/scripts/reload_website-1658.sh >/dev/null 2>&1
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