更新结构中的映射式数据结构

最近发现不少小伙伴都对Golang很感兴趣，所以今天继续给大家介绍Golang相关的知识，本文《更新结构中的映射式数据结构》主要内容涉及到等等知识点，希望能帮到你！当然如果阅读本文时存在不同想法，可以在评论中表达，但是请勿使用过激的措辞~

package main

import "fmt"

type State string

const (
    // PASS check passed.
    PASS State = "PASS"
    // FAIL check failed.
    FAIL = "FAIL"
    // WARN could not carry out check.
    WARN = "WARN"
    // INFO informational message
    INFO = "INFO"
    // SKIP for tests skipped
    SKIP = "SKIP"
)

// SummaryLevelWise is a summary of results of control checks run CIS Levelwise
type Something struct{
    SummaryLevelWise map[string]*Summary
}

// Summary is a summary of the results of control checks run.
type Summary struct {
    Pass int `json:"total_pass"`
    Fail int `json:"total_fail"`
    Warn int `json:"total_warn"`
    Info int `json:"total_info"`
    Skip int `json:"total_skip"`
}


func main() {

    s := &Something{}
    s.doingSomething()
    // This is one way I tried to update the map[string]*struct variable
    s.SummaryLevelWise["1"].Pass, s.SummaryLevelWise["1"].Fail, s.SummaryLevelWise["1"].Warn, s.SummaryLevelWise["1"].Info, s.SummaryLevelWise["1"].Skip = 0,0,0,0,0

   // Another way that didn't work
   // s.SummaryLevelWise["1"] = &Summary{0,0,0,0,0}

}


func summarizeLevel(summary *Summary) {
    switch PASS{
    case PASS:
        summary.Pass++
    case FAIL:
        summary.Fail++
    case WARN:
        summary.Warn++
    case INFO:
        summary.Info++
    case SKIP:
        summary.Skip++
    }
}


func(something *Something ) doingSomething(){

    level1 := "1"

    for i:=0; i<10; i++ {
        summarizeLevel(something.SummaryLevelWise[level1])
    }
    fmt.Println(something)
}

我得到的错误是

恐慌：运行时错误：无效的内存地址或零指针 取消引用 [信号 sigsegv：分段违规代码=0x1 addr=0x0 电脑=0x1091ac4] goroutine 1 [运行]: main.summarizelevel(...) /users/i345678/go/class="lazy" data-src/github.concur.com/test/test/main.go:68 main.(*something).doingsomething(0xc00000c028) /users/i345678/go/class="lazy" data-src/github.concur.com/test/test/main.go:89 +0x64 main.main() /users/i345678/go/class="lazy" data-src/github.concur.com/test/test/main.go:58 +0x44 退出状态 2

级别字符串的值为“1”和“2”。

解决方案

func main() {




    s := &Something{}
    // Intialize map.
    s.SummaryLevelWise = map[string]*Summary{}
    //s.SummaryLevelWise["1"].Pass, s.SummaryLevelWise["1"].Fail, s.SummaryLevelWise["1"].Warn, s.SummaryLevelWise["1"].Info, s.SummaryLevelWise["1"].Skip = 0,0,0,0,0
    s.SummaryLevelWise["1"] = &Summary{0,0,0,0,0}
    s.doingSomething()


}

地图可以为零。因此需要初始化它们。

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