![[codewars_python]Sum](https://static.528045.com/imgs/42.jpg?imageMogr2/format/webp/blur/1x0/quality/35 "[codewars_python]Sum")
Instructions
In this kata, you must create a digital root function.
A digital root is the recursive sum of all the digits in a number. Given n, take the sum of the digits of n. If that value has more than one digit, continue reducing in this way until a single-digit number is produced. This is only applicable to the natural numbers.
Here's how it works:
digital_root(16)
=> 1 + 6
=> 7
digital_root(942)
=> 9 + 4 + 2
=> 15 ...
=> 1 + 5
=> 6
digital_root(132189)
=> 1 + 3 + 2 + 1 + 8 + 9
=> 24 ...
=> 2 + 4
=> 6
digital_root(493193)
=> 4 + 9 + 3 + 1 + 9 + 3
=> 29 ...
=> 2 + 9
=> 11 ...
=> 1 + 1
=> 2
My solution:
def digital_root(n):
lst = [int(x) for x in str(n)]
result = sum(lst)
if result < 10:
return result
else:
return digital_root(result)
Best solution:
def digital_root(n):
return n if n < 10 else digital_root(sum(map(int,str(n))))
